Question

Calorimeter Prelab - Define Specific Heat. 2) In what direction does heat flow? 3) (M SH AT) Warm Water- [(M SH aT) * Cold Water+ (Calorimeter Constant x AT)] a) Indicate what the following symbols represent M for Warm Water SH AT of Cold Water b) What is the general equation for q. 4) Using the data and the equation provided below, calculate the calorimeter constant. Refer to the example provided in the laboratory procedure Sample data for the calculation of the calorimeter constant Mass of Cold water Initial temperature of cold water and calorimeter 80.3 g 25.0 °C 100.0 g Mass of hot water Initial temperature of hot water Final temperature reached of cold, hot water, and calorimeter. 27.0°C 98.5 C Temperature change, AT, hot water Temperature change, AT, cold water, and calorimeter

Answer 1

a) Specific heat : Amount of heat required to raise temperature by 1⁰c or 1 K of unit mass of a substance .

Unit : J/g^oc .

b)

Heat flows from hot body to cold body.

C)

M is mass of water.

SH is specific heat.

$\Delta$T is temperature change.

d)

q = M× SH × $\Delta$ T.

e)

Temperature change of hot water

= Final temperature - initial temperature = (27 -98.5) = - 71.5^oc

Temperature change of cold water

= Final temperature - initial temperature = ( 27 -25) = 2^oc

Now

Mass of hot water × specific heat × temperature change

= - (Mass of cold water × specific heat × temperature change + Calorimeter constant × temperature change ) .

Slecific heat of water = 4.184 J/g^oc.

Putting the given values

100 × 4.184 × ( 27 - 98.5) = - {( 80.3 × 4.184) × (27 - 25) + C× (27 - 25}

Or, - 29915.6 = - {(335.97 ×(2) + C×(2)}

Or, 29915.6 = 671.95 + 2C

Or 2C = (29915.6 - 671.95)

Or, 2C = 29244.1

Or, C = (29244.1/2)

Or, C = 14622.05 J/K.

Or, C = 14.62 KJ/K.