Question

(See p. 413 and Fig. 7-11) ki E+ SHE-S Noncompetitive inhibition: the inhibitor attaches k2 kz to only one type of site and t

Please show the rate law.

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Answer #1

km= [E][S]/[E.S] E+ S = E.S

rp= k[E.S] rp = k[E][S]/Km-----(I)

[Et] = [E] + [E][S]/Km + [E][I]/Kt + [E.S][I]/Kt + [E][S][I]/KmKt

THEREFORE

take [E] common,

then substitute and you will get the value of rp as in the question

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