Question

Can answer in multiple choice way

1. The following is FALSE about acid and bases: a. Weak acids generate weak conjugated bases. b. Acids can only protonate bases with higher pka values. c. Metal ions can be acids. d. Acid-base reactions favor weaker acids. 5. What are the expected products of the following reaction? 2. Which molecule is the most acidic? a. HCN (pKa = 4.7) . b. Isopropanol (pka - 17.1) c. water (pKa - 15.7) d. ammonia (pka = 33) If Hooh + HC 3. Choose the correct equilibrium constant (K) for the reaction: H,So, + 2KOH = 2H,0 + K,SO a. IK,804|H2OJ [K,804[H2OP H.SO JIKOH a. H, SOJKOH b. TH,80 KOHT [H,80][KOHT (K.80.JH,01 c. R.80.11H,OP d. Choose the Lewis acid a. AlCl3 b. 6. What is the outcome of the following reaction? c. HỌC=CH 2 HẠC CH,

Answer 1

1. a.Weak acids generate weak conjugated bases

This is a false statement because weak acids generate strong conjugate bases and vice versa.

2.a. HCN(pka=4.7)

pKa = -log[Ka]

Ka is dissociation constant of acid, the greater the Ka value greater the acid dissociates and greater is its acidity.

Therefore, stronger acids have lower pka values and vice versa.

HCN has lowest pka value therefore strongest acid in the given options.

3. b. Keq = [K₂SO₄][H₂O]²/[H₂SO₄][KOH]²

Keq equilibrium constant is the the ratio of product of concentrations of product to the product of concentration of the reactants raise to the power their coefficients in the balanced chemical reaction.

H₂SO₄ + 2KOH <==> 2H₂O + K₂SO₄

Keq = [H₂O]²[K₂SO₄]/[H₂SO₄][KOH]²

4.a. AlCl₃

According to Lewis a species is an acid if it is electron deficient and accept lone pair of electrons and Aluminium chloride is electron deficient it has three electrons in its valence shell so when it forms covalent bond with 3 chlorine atoms it form 3 single bond. And aluminium has a sextet , thus incomplete octet and so electron deficient.

5.b. H₃COO^- + ​​​​(H₃C)₃N⁺H

nitrogen of trimethylamine abstracts the acidic Proton of carboxylic acids because the nitrogen of trimethylamine contains lone pair of electrons are therefore basic in nature and a base abstracts proton.

6.c.

The following step will produce the product given in option C