Question

Given the chemical reaction Al + 3AgNO3 → Al(NO3)3 + Ag how many milliliters of 0.544...

Given the chemical reaction

Al + 3AgNO3 → Al(NO3)3 + Ag

how many milliliters of 0.544 M AgNO3 will react with 1.00 g of Al?

Answer in (mL)

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Answer #1

T The balanced chanical equation is - М+ 3 Ну год — A (No3), +39 Molur muss a moles of n = 26-98 gmpmole al = 10 gm 26-98 gen

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