Question

what concentration of acetic acid (pka=4.76) and acetate would be required to prepare a .15 M buffer solution at pH 5.0?

What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.07 Note that the concentration, the pH, or both values may differ from that in the first question. Strategy 1. Rearrange the Henderson-Hasselbalch equation to solve for the ratio of base (acetate) to acid (acetic acid). (AVHA). 2. Use the mole fraction of acetate to calculate the concentration of acetate. 3. Calculate the concentration of acetic acid. Step 1: Rearrange the Henderson-Hasselbalch equation to solve for HAL The Henderson-Hasselbalch equation is A) pH = pk, +10HA Use the Henderson-Hasselbalch equation to solve for if the solution is at pH 5.0. Enter your answer as a number. For example, 9.6. Do not enter a formula like 100+2 99995.24

Answer 1

Aty guen: Pka Ceng coon)= 4. H PH5.0 Applycina Hendesson- Hagelbalch equaten Pka t loa lconj geik ba Cweak ac Pn Pkat log eco

Substituding the valug eqn +og 5.0 . 4. 76= ち0 log coon 0.24 CMgcook CeM3co6 o 24 'Ca Coo olog 1-73780 083 Cancoa we knaw uat Ccngcoo] co Buffer molasty O.15M grven Bufe] O 15M Thug Fimn a we haue 73780083 [Cuzcoon CMg co 5 eqn , We haue Substrauting Lg coo 380083 u Coo o5M

2.138 0083cgcoon 015M seug coo 015 a.1378 o0 83 ০. ০51 न8৪4৭৭7 O.0518 M Ceng coo o15 = o.15-O.059 7884197 z0.015a I 500 3 M =o. 0452 M