Question

Data matches Cashew, type of nut 4 matches Almond 2.929 3. 2008 mass of weighing dish, g initial mass of nut and weighing dish, g 3.9289 initial water temperature, °C 22.7°C 32.7°C 4.6549 22.4°C 41.4°C 3.380 g final water temperature, °C 3.2750 mass of nut residue and weighing dish, g Calculations initial mass of nut, s 0.999 g mass of nut residue, g 0.3466 mass of nut oil burned, g change in water temperature, °C 10.0°C mass of water in calorimeter, kg 200mL total amount of energy released, Cal amount of energy released per g of nut oil burned, Cal g' energy per g of nut, Cal g! (nut oil accounts for 75% of the Calories) * accepted amount of Calories per g, Cal g 190 percent difference

only need help for the almond side not the cashew side. thank you sm!!!!! :)

Answer 1

Calculations for almond

(1.) initial mass of nut = (initial mass of nut and weighing dish) - (mass of weighing dish)

initial mass of nut = (3.928 g) - (2.929 g)

initial mass of nut = 0.999 g

(2.) mass of nut residue = (mass of nut residue and weighing dish) - (mass of weighing dish)

mass of nut residue = (3.275 g) - (2.929 g)

mass of nut residue = 0.346 g

(3.) mass of nut oil burned = (initial mass of nut) - (mass of nut residue)

mass of nut oil burned = (0.999 g) - (0.346 g)

mass of nut oil burned = 0.653 g

(4.) Change in water temperature = (final water temperature) - (initial water temperature)

Change in water temperature = (32.7 ^oC) - (22.7 ^oC)

Change in water temperature = 10.0 ^oC

(5.) volume of water in calorimeter = 200 mL

mass of water in calorimeter = (volume of water in calorimeter) * (density of water)

mass of water in calorimeter = (200 mL) * (1.00 g/mL)

mass of water in calorimeter = 200 g

mass of water in calorimeter = 0.200 kg

(6.) total amount of heat released = (mass of water in calorimeter) * (specific heat water) * (Change in water temperature)

total amount of heat released = (0.200 kg) * (1 Cal/kg.^oC) * (10.0 ^oC)

total amount of heat released = 2 Cal

(7.) amount of energy released per g of nut oil burned = (total amount of heat released) / (mass of nut oil burned)

amount of energy released per g of nut oil burned = (2 Cal) / (0.653 g)

amount of energy released per g of nut oil burned = 3.06 Cal/g

(8.) energy per g of nut = (amount of energy released per g of nut oil burned) / (0.75)

energy per g of nut = (3.06 Cal/g) / (0.75)

energy per g of nut = 4.08 Cal/g

(9.) accepted amount of Calories per g = 160 Cal/g

(10.) percent difference = [(accepted amount - experimental amount) / accepted amount] * 100

percent difference = [(160 - 4.08) / 160] * 100

percent difference = (155.92 / 160) * 100

percent difference = (0.974) * 100

percent difference = 97.4 %