Walnut
Mass = 0.49 g
Cwater = 1 Cal/g degC
Temp Change = 5 deg C
Q = Mass * C* Temp Change
= 0.49 g * 1 Cal / g deg C * 5 deg C
= 2.45 Cal
= 0.00245 kCal
Energy released per grm = 0.00245 kCal / 0.49 g = 0.005 kCal/g
Marshmallow
Mass = 0.2 g
Cwater = 1 Cal/g degC
Temp Change = 0 deg C
Q = Mass * C* Temp Change
= 0.2 g * 1 Cal / g deg C * 0 deg C
= 0 kCal
Energy released per grm = 0 kCal/g
Chip
Mass = 1.19 g
Cwater = 1 Cal/g degC
Temp Change =6 deg C
Q = Mass * C* Temp Change
= 1.19 g * 1 Cal / g deg C * 6 deg C
= 7.14 Cal
= 0.00714 kCal
Energy released per grm = 0.00714 kCal / 1.19 g = 0.006 kCal/g
Data Table 2: Caloric Calculations Walnut Marshmallow (Jumbo) Tortilla Chip Food Item Description: Mass of food,...
24-26 Please show how you got the answer. 26 I know you add them up 13 kcal/g + 28g= ? but I'm not sure do you divide them Walnut Marshmallow (Jumbo) Tortilla Chip 5.98g 9.59 5.87 5.49g 9.39 3.96 .49g .20g 1.91g Food Item Description: Mass of food, cup, and clip - initial (g) Mass of food, cup, and clip - final (9) Mass of burned food (g) Observations of Flame (intensity, length of time burning, etc.) Water temp -...
Calculations are based on one trial. To receive full credit, you must SHOW ALL OF YOUR WORK. Answers that do not have complete work shown will be marked as incorrect. Workstation : Part A: Specific Heat of an unknown Metal 1. Unknown number 1326 18.09 8.37 2. Mass of unknown metal 9 3. Mass of empty calorimeter 9 Trial 1 Trial 2 Mass of calorimeter + water 45.23 g g Mass water 36.86 g g Initial Temperature of metal 100...
need help with the calculations please. Paragraph Styles Font Section Please type your name here: Please be am work below. I would recommend wing your work on a piece of arch and then nping any work below. For dimensional analysis, please either insert an equation or we the notation below as an example for the common or 234 Tartan i Word select "Insert and then "Equation Data and Calculations: 1kg Record data for Steps 1-8 here. For steps 9-13, do...
Lab-10: Calorimetry: Specific Heat of a Metal DATA SHEETS: Reference: Chapter Notes-10 and Lab Manual (Pages 64 to 70) Use the following You Tubes to get more information https://youtu.be/8gHFOL2990U https://youtu.be/HlvilF6MI9c Calculate the Specific Heat and identify the Metal Observation Mass Mass of Metal (ml): 87.87 g Mass of polystyrene cup (m2): 2.32 g Mass of cup with water (m3): 72.82 g Mass of water in the cup (m3-m2): 70.5 g Temperature Initial temp. of Metal (the boiling water temperature (t1):...
Please help me solve this problem. (5 points) Table 1: Heat Content of a Snack Food using Calorimetry-see below for calculations PROPERTY TRIAL1 TRIAL 2 TRİAL3 Dorito Snack Used Volume of water (mL) Mass of water (g) Mass of snack (g) Initial temperature (°C) Final temperature (°C) Change in temperature (°C) Heat absorbed by water (cal) 9 ml 个1 19 ml 991 o 346 24.5 33.1 c 8,6 C 2 53 04Ss 24.S C 37.S Heat released by snack (food...
157q - Chen PART TWO: DATA AND RESULTS Metal: Aluminum Ca=0.217 Cal/ 12)-speeifie quarta Data Item Trial 1 Trial 2 1. Mass of metal 86-bg 50.09 2. Mass of calorimeter 4,4 g 3. Mass of calorimeter and water 124.4 g 4. Mass of water 152-6 g 120g 5. Initial temperature of water 24°C 23°C 6. Initial temperature of the metal 25°C 75°C 7. Final temperature of the mixture 24.11°C 55.7ook See the attachment 8. Calculation of the heat energy gained...
In this experiment, you will determine and compare the quantity of heat energy released in three exothermic chemical reactions through application of Hess’s law. Reaction 1: NaOH(s) → Na+(aq) + OH-(aq) + x1 kJ Reaction 2: NaOH(s) + HCl(aq) → H2O(l) + Na+(aq) + OH-(aq) + x2 kJ Reaction 3: NaOH(aq) + HCl(aq) → H2O(l) + Na+(aq) + OH-(aq) + x3 kJ In order to accurately measure the heat released in each reaction, we will be using a calorimeter. As...
86.bg PART TWO: DATA AND RESULTS Metal: Aluminum (Cal = 0.217 cal/qE)-specific granity Data Item Trial 1 Trial 2 1. Mass of metal 50.og 2. Mass of calorimeter 3. Mass of calorimeter and water 124.49 4. Mass of water 120g 5. Initial temperature of water 24°C 23°C 6. Initial temperature of the metal 25°C 75°C 7. Final temperature of the mixture 21.11°C 152.6 g 8. Calculation of the heat energy gained by the water, Q Trial Onc: Trial Two: see...
Please help with completing lab with the following measurements. Thank you. Final Temperature of water is 28 C Mass (9) Water 200 Metal Ball 60 Initial Temperature (°C) Final Temperature (°C) 21 81 21 cusing T-1 cusing T cusing T+1 Lab 9: Specific Heat In this lab, you will measure the specific heat of the metal ball in your kit. To do this, you will heat it up to nearly 100°C and then submerge it in room temperature water. After...
1. Which of the following is not considered a nutrient a Vitamin B. Water c.Carbohydrate (d) Alcohol e Mineral 2. For which of the following causes of death does a person's diet play a part? a. Lung disease (6) Cancer Chronic lower respiratory diseases d. Infections of the blood e AIDS 3. Researchers repeatedly report that people who consume a variety of foods such as fruits, vegetables, legumes, nuts, and whole grains have reduced risks of which of the following...