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10.1 Practice basic skills (grams, moles, g/mol, mol/L, dilution, stoichiometry): (a) Mow many grams of Br2 are produced when
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Answer #1

a) according to equation , 3mole Br2 is produced when 2 mole of FeBr3 react with 3 mole Cl2

Given mass of FeBr3 = 1.5g

Mole of FeBr3 = given mass/molar mass

=1.5/295.56

= 0.005mole

Now since cl2 is given in excess we don't have to worry about mole of Cl2

Since 2mole FeBr3 react to produce 3 mole Br2

Then 0.005mole FeBr3 will produce x mole Br2

x = 0.005*3/2 mole

=0.0075mole Br2

One mole Br2 = 159.8g

0.0075 mole Br2 = 159.8*0.0075

=1.198g of Br2 is produced .

b) Molarity of cl- = number of mole /volume in L

Now,

According to equation 2 mole of FeBr3 produce 2 mole of FeCl3

That means equal moles

So 0.005 mole of FeCl3 is produced

One unit of Fecl3 has 3 Cl- ions

So 0.005 mole of Fecl3 will have 0.005×3 mole ions of Cl-

Volume in L = 0.5L

So molarity = 0.005×3÷0.5

= 0.03 mole/L

(c). Molarity = mole/Volume in L

Hence , no. Of mole = Molarity × volume in L

In both solutions , number of moles will remain same

Hence , M1 × V1 = M2 ×V2

18 × V1(ml) = 2 × 750 ml

V1 = 83.33 Ml

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