a) according to equation , 3mole Br2 is produced when 2 mole of FeBr3 react with 3 mole Cl2
Given mass of FeBr3 = 1.5g
Mole of FeBr3 = given mass/molar mass
=1.5/295.56
= 0.005mole
Now since cl2 is given in excess we don't have to worry about mole of Cl2
Since 2mole FeBr3 react to produce 3 mole Br2
Then 0.005mole FeBr3 will produce x mole Br2
x = 0.005*3/2 mole
=0.0075mole Br2
One mole Br2 = 159.8g
0.0075 mole Br2 = 159.8*0.0075
=1.198g of Br2 is produced .
b) Molarity of cl- = number of mole /volume in L
Now,
According to equation 2 mole of FeBr3 produce 2 mole of FeCl3
That means equal moles
So 0.005 mole of FeCl3 is produced
One unit of Fecl3 has 3 Cl- ions
So 0.005 mole of Fecl3 will have 0.005×3 mole ions of Cl-
Volume in L = 0.5L
So molarity = 0.005×3÷0.5
= 0.03 mole/L
(c). Molarity = mole/Volume in L
Hence , no. Of mole = Molarity × volume in L
In both solutions , number of moles will remain same
Hence , M1 × V1 = M2 ×V2
18 × V1(ml) = 2 × 750 ml
V1 = 83.33 Ml
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