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What is the angle that allows you to throw the ball the farthest distance given that...

What is the angle that allows you to throw the ball the farthest distance given that you are standing a height h above the target? Hints: 1. you can simplify the math recognizing that h = xf tan (\phi) 2. also you can simplify your answer using cot (\alpha) = tan( (\pi/2) - \alpha )

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