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2. The Bohr model holds for any one-electron atom. Calculate the lowest energy level of the helium ion, He. (Hint: Examine t
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Answer #1

Ans 2:

According to Bohr model, energy of hydrogen/hydrogen like systems (single electron systems) is given by,

E = - RH .(Z2/n2)

Where, E = energy of the electron in ‘nth’ orbit

               RH = Rydberg’s constant = (e4.m)/(8.h2.ꞓo2) = 2.18 x 10-18 J

               e = charge on the electron = 1.6 x 10-19 C

               m = mass of the electron =9.10938356 × 10-31 kg

               h = plank’s constant = 6.62607004 × 10-34 m2 kg / s

               .ꞓo = relative permittivity (C2/J.m

In the Helium ion (He+), number of protons (Z) present = 2, No of electrons = 1

For the ground state of ‘He+’ ion, n = 1

E = - RH .(Z2/n2) = -2.18 x 10-18 J (4/1) = -8.72 x 10-18 J

Lowest energy of ‘He+’ ion = -8.72 x 10-18 J

{Here, the negative sign indicates that electron is bound to helium nucleus}

Ans 3:

E = - RH .(Z2/n2) = - (e4.m)/(8.h2.ꞓo2) (Z2/n2)

Units of right hand side equation:

(e4.m)/(8.h2.ꞓo2) (Z2/n2) = (C4 . Kg)/(m4 Kg2 s-2 x C4 J-2.m-2) = Kg-1. m-2 . s2 . J2

We know that 1J = 1 Kg. m2.s-2

So, Kg-1. m-2 . s2 . J2 = J-1.J2 = J (Unit of energy)

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