= Horeaction - Goreaction
Here, Goreaction = GoNO - GoNOCl = 87.6-66.1 = 21.5 kJ/mol
And Horeaction = HoNO - HoNOCl = 91.3-51.7 = 39.6 kJ/mol
Now, = 39.6 - 21.5 = 18.1
And Degree of dissociation of NOCl = Goreaction/Horeaction = 21.5/39.6 = 0.543
A Review | Constants | Periodic Table You place 1.45 mol of NOCl(g) in a reaction...
A mixture of 0.1182 mol of O2, 0.05082 mol of NOCl, 0.1918 mol of NO2, and 0.1196 mol of Cl2 is placed in a 1.0-L steel pressure vessel at 604 K. The following equilibrium is established: 1 O2(g) + 2 NOCl(g) 2 NO2(g) + 1 Cl2(g) At equilibrium 0.03160 mol of NOCl is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of O2, NOCl, NO2, and Cl2. Peq(O2) = . Peq(NOCl) = . Peq(NO2) = . Peq(Cl2)...
Consider the reaction: 2NO(g) + Cl2(g) → 2NOCI(g) Given the following table of thermodynamic data, Substance NO (g) Cl2(g) NOCI (g) AH (kJ/mol) 90.3 0 sº (/mol.K) 210.7 223.0 51.7 261.6 Calculate Ahºrxn and AS rxn and determine the temperature at which the reaction switches from being spontaneous to being non-spontaneous.
Consider the following reaction: 2 NO(g) + Cl2(g) = 2 NOCI() The reaction is at equilibrium at 125 °C with PNo = 1.66 bar, PcI2 = 0.830 bar, and PNoci = 1.09 bar. (a) Calculate the value of the equilibrium constant of this reaction at 125 °C. (b) Calculate the value of AGº of this reaction at 125 °C. Give you answer with 3 significant figures and in the units kJ/mol. (c) Given the following additional information and assuming that...
Part A Use the data below to calculate AG for the decomposition of nitrosyl chloride at 25°C when the partial pressures are 5.00 atm of NOCI, 1.00 x 10-3 atm of NO, and 1.00 x 10-3 atm of Cl2. 2NO(g) + Cl2(g) + 2NOCI(8) Substance and State AG°f (kJ/mol) Cl2(g) 0 NO(g) 87.6 NOCI(g) 66.1 Express your answer in kilojoules per mole to one decimal place. VO ΑΣΦ ? AG = kJ/mol Submit Previous Answers Request Answer
Use the data below to calculate AG for the decomposition of nitrosyl chloride at 25°C when the partial pressures are 5.00 atm of NOCI 1.00 x 10-3 atm of NO, and 1.00 x 10-3 atm of Cl, 2NO(g) + Cl2(g) + 2NOCI(g) Substance and State AG: (kJ/mol) Cl(8) 0 NO(g) 87.6 NOCI(8) 66.1 Express your answer in kilojoules per mole to one decimal place. ΠΠΙ ΑΣΦ AG= kJ/mol Submit Request Answer
Review Constants Periodic Table Benzoic acid of mass 1.45 g is reacted with oxygon in a constant volume calorimeter to form H20(l) and CO2 (g) at 298 K The mass of the water in the inner bath is 1.70 x 10g The temperature of the calorimeter and its contents rises 2.82 K as a result of this reaction. Part A K Cp.m(H2O,1) - 75.3 J. mol Calculate the calorimeter constant. The standard enthalpy of combustion of benzoic acid at 298...
Consider the reaction: 2NO(g) + Cl2(g) 2NOCl(g) Given the following table of thermodynamic data, Substance ∆Hfo (kJ/mol) So (J/molK) NO (g) 90.3 210.7 Cl2 (g) 0 223.0 NOCl (g) 51.7 261.6 Calculate ∆Horxn and ∆Sorxn and determine the temperature at which the reaction switches from being spontaneous to being non-spontaneous. Please show all work. Provide equations used. Please use correct significant figures and correct units in answers.
Consider the reaction: 2NO(g) + C12(8) + 2NOCI(g) Given the following table of thermodynamic data, AHF (kJ/mol) Substance NO (8) Cl2 (8) NOCI (8) 90.3 0 sº (l/mol.K) 210.7 223.0 261.6 51.7 Calculate Ahºrxn and Asºrxn and determine the temperature at which the reaction switches from being spontaneous to being non- spontaneous.
What is ΔG°rxn for the following reaction? 2NO(g) + Cl2(g) → 2NOCl(g) Substance ΔG°f(kJ/mol) NOCl(g) 66.39 NO(g) 86.49 Answer choices: 40.40 kJ -20.10 kJ -40.20 kJ 152.09 kJ -175.20 kJ
Nitrogen AHºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) N2 (g) 0 0 191.6 472.7 455.6 153.3 N(g) NH3 (g) -46.1 -16.5 192.5 NH3 (aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 NO (g) 90.3 86.6 210.8 NOCI (g) 51.7 66.1 261.8 NO2 (g) 33.2 51.3 240.1 N20 (g) 82.1 104.2 219.9 N204 (8) 9.2 97.9 304.3 Consider the reaction N2(9) + 202(9)—2NO2(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for this reaction at 298.15K...