For the reaction below calculate Kif H2O is initially 0.75mol in 2.0L and at equilibrium H2O...

Question

Question

Answer 1

Answer #1

Initial concentration of H2O = mol of H2O / volume in L

= 0.75 mol / 2.0 L

= 0.375 M

ICE Table:

[H2] [02] [H20] initial 0.375 change +2x +1x -2x equilibrium +2x +1x 0.375-2x

Given at equilibrium,

[H2O] = 0.25

0.375-2x = 0.25

x = 0.0625

Equilibrium constant expression is

Kc = [H2O]^2/[H2]^2[O2]

Kc = (0.375-2x)^2/(+2x)^2(+1x)

Kc = (0.375-2*0.0625)^2/(+2*0.0625)^2(+1*0.0625)

Kc = 64

Answer: 64

Answer 2

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