"what is the difference between parallel and bisecting technique"
In the paralleling technique, the beam alignment device is used to hold the receptor parallel to the long axis of the tooth. Examples of beam alignment devices include XCP (Extension, Cone, Paralleling) and BAI beam alignment devices (Rinn).
The bisecting technique or the bisecting-angle technique is one of the methods used to expose periapical images. The bisecting technique is developed based on the principle of “rule of isometry.” The rule of isometry states that if two triangles have equal angles and share a common side, those triangles are considered equal. In dental imaging, this principle is used to form two imaginary equal triangles.
The central ray in the correct bisecting technique is directed at 90 degrees (vertical) to the imaginary bisector. Correct vertical angulation results in the dental image with the same size as that of the real teeth.
4. What is the difference between using brainstorming and the Delphi technique for risk identi- fication? What are some of the advantages and disadvantages of each approach? Describe the contents of a risk register and how it is used in several risk management processes.
- What is the difference between serial and parallel registers? and What types of flip-flops are preferable for serial registers? why? - Explain the operation of the serial 3 bit register and draw its timing diagrams.
At what rate must the potential difference between the plates of a parallel-plate capacitor with a 2.9 μF capacitance be changed to produce a displacement current of 1.3 A?
Problem 18.30 What is the potential difference between the plates? The plates of a parallel-plate capacitor are 350 mm apart, and each carries a charge of magnitude 81.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 3.00*10° V/m Submit ▼ Part B What is the area of each plate? A- Submit PartC What is the capacitance?
The potential difference between a pair of oppositely charged parallel plates is 430 V. (a) If the spacing between the plates is doubled without altering the charge on the plates, what is the new potential difference between the plates? V (b) If the plate spacing is tripled while the potential difference between the plates is kept constant, what is the ratio of the final charge on one of the plates to the original charge? (Qfinal / Qinitial)
The potential difference between the plates of a parallel plate capacitor is 45 V and the electric field between the plates has a strength of 850 V/m. If the plate area is 4.0
A proton is accelerated through a 3.11 kV potential difference and directed between parallel plates separated 12.3 mm as shown below. The EMF of the battery is 10.0 V. What is the magnitude and direction of the uniform magnetic field between the plates that allows the proton to travel undeflected?
The potential difference between the two parallel plates shown in the drawing is 200 V. The distance between the plates is 0.03 meters. A particle (mass = 1 x 10-3 kg) with a charge of +5 C is released from rest at the positive plate. (a) What is the kinetic energy of the particle when it strikes the negative plate? (5 pt) (b) What is the speed of the particle when it strikes the negative plate? (10 pt) (e) What...
Using the IRR technique. Define the technique. Discuss the difference between this method and the payback method, discounted payback method, and NPV method. Remember to carry out your answers at least two decimal places. Year Project A Project B Project C 2018 ($3,000,000) ($3,000,000) ($3,200,000) 2019 $0 $975,000 $985,000 2020 $600,000 $975,000 $925,000 2021 $900,000 $975,000 $1,000,000 2022 $3,000,000 $1,000,000 $950,000 The projects are discounted at 10% rate Project A Year Cash flows Present Value Factor( C (1.10)-n) Present Value...
A parallel plate capacitor is initially filled with air. A potential difference V0 is produced between the plates and then the power supply is disconnected. After the power supply is disconnected a dielectric of dielectric constant k is inserted between the plates. What is the new voltage Vf between the plates? Group of answer choices Vf = V0 / k Vf = kV0 Vf = (1/2)(k + 1)V0 Vf = V0