Hypergeometric Formula.. Suppose a population consists of N items, k of which are successes. And a random sample drawn from that population consists of n items, x of which are successes. Then the hypergeometric probability is:
h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]
This is a hypergeometric experiment in which we know the following:
We plug these values into the hypergeometric formula as follows:
h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]
h(2; 52, 5, 26) = [ 26C2 ] [ 26C3 ] / [ 52C5 ]
h(2; 52, 5, 26) = [ 325 ] [ 2600 ] / [ 2,598,960 ]
h(2; 52, 5, 26) = 0.32513
Thus, the probability of randomly selecting 2 red cards is 0.32513.
Suppose we randomly select 5 cards without replacement from an ordinary deck of playing cards. What...
Suppose we randomly select 5 cards without replacement from an ordinary deck of playing cards. What is the probability of getting exactly 2 red cards (fi.e, hearts or diamonds)? Select one: O C O a. 0.22640 b, 0.32513 e. 0.29235 d.0.44259 e.0.19277
Suppose you are asked to draw ten cards without replacement from a regular deck of 52 playing cards. What is the probability of getting exactly 3 Queens or exactly 3 Kings (or both)? I also need help with the other two, please provide an explanation with your work and I will promptly give a positive rating. С https://drive.google.com/drive/folders/lyinXTMXuBMbKU3nO0oRbVKV ug pg 1 Yrmu (18) Suppose you are asked to draw 5 cards from a deck of 52 regular playing cards (a)...
We draw 5 cards randomly, and without replacement, from a standard 52-card deck. Find the probability that we get (a) three cards of one suit and two of another (b) at least three hearts
1. We draw 5 cards randomly, and without replacement, from a standard 52-card deck. Find the probability that we get (a) three cards of one suit and two of another (b) at least three hearts
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