Question

Calculate the pH of each of the following strong acid solutions. (a) 0.00418 M HIO4 pH = (b) 0.365 g of HCIO4 in 25.0 L of solution pH = (c) 45.0 mL of 7.30 M HIO4 diluted to 4.50 L pH = (d) a mixture formed by adding 31.0 mL of 0.00172 M HIO4 to 28.0 mL of 0.00529 M HCIO4 pH =

Answer 1

acid SodconS y oncent Single formuta oni2ed m au fuly alidsi they gvan by tthe CHe ave.oacid va far ouo vi's Yation, thms basie acids. Co 0.00418M o HI04 Camentration otOiowsH 0.00418 M Melo -eg (o.00419)- 2.38 (Aus (b) 0.3652 01 H04 in 25.0L01 ueon Molieular waigldt o Ha04= 100.46lmel 05650 6 0. 5650 Hl04 = 00 6 /mob o HCl 04 3.633x10 weles of Hel04 .633X1ole :. loncentnation ol Helo4 ohdisn 25,0 L 2 1.4532x10 M Concntradtion o H ions 1.4532X 16M -Veg (1-4532x16)3 84 (Ans)

is diluted to 4.50L 7.0MX 450m Srdion 4.50L -73 M. -les (or073) 1.14 (Aus) (4) a muxture for md by adding bl.mt oo00172M HJO4 to 28 wl ot o. 00 529M o Hd04 mLX0.00172 M) + (28wLy o005 29A) (encwdration of ius 3.4 14X10 -Ves CH-e(A\4 X102) = 2:47 (Au)