Question

Calculate the pH of each of the following strong acid solutions.



(a) 0.00332 M HBrO₄

pH =  



(b) 0.592 g of HIO₄ in 19.0 L of solution

pH =  



(c) 65.0 mL of 6.90 M HBrO₄ diluted to 1.90 L

pH =  



(d) a mixture formed by adding 66.0 mL of 0.00829 M HBrO₄ to 31.0 mL of 0.000900 M HIO₄

pH =  

Answer 1

a) 0.00332 M H Brou HPH. — 249 е E-log (0.00332) pH = 20479 ? b. 0.592 g of HIOy in 19.0L of solution - - molodost weig, е ито, = 227.94 a/mo.g 0.592 8. HIO4 = ora sou moe .? 2.597x10-3 mol 19.0L oca7 x 10 mol si- Solution contain L 2:507 X10 IL 1 2 2.597x10 M axi-2; 2 1.367X163(M). pH = -log (1-367X163) [PV- 3 869 | c. 6500 mL of 6.90 m HB nou to igolit => 65.0 me x: 6.90 M =1900mL XS, S, -0.2360 (M) .: pH = -log(0• 2360) PH= 0.626] d. to 100 prod 66 mL 0.00829 M Honout 31 mL 0.0000M HIOU => strength of HBnOn > 0.00829 866 - 564X103 66731_ 58643 Stroength of HeIon => 0.0009831 – 4.227x 104 - Total = (5064X163 +41227X164) = 60062x16% in pH = -log (6.062x103) = 2.217 pH = 2.217