Question

21. -/0.1 points 0/4 Submissions Used Calculate the pH of each of the following strong acid solutions. (a) 0.00241 M HIO4 PH - (b) 0.352 g of HI in 50.0 L of solution pH = (c) 64.0 mL of 1.10 M HIO4 diluted to 4.70 pH = (d) a mixture formed by adding 89.0 mL of 0.00647 M HIO4 to 73.0 mL of 0.00362 MHI pH-L

Answer 1

Strong cards dissociate completely in their aqueous solutions 0.00241 M H104 HIO4 - H+ + 10 (H104 ] = [H +] = 0.00zuim pH = -10g [H +] = -10g 10.002413= 2.62 (6) Malarity = mars malar mars X Volume 0-352 g berega mol X 50L +37191 = Bogle QeAA 5.5M = [H* ] pH = -log(H+] = -log(809] = -0.74 moles before dilution = moles after delution M, W, = M₂ k 1. 10MX 64 ml = M₂ x 4700ml M = 1.10MX 64 and 0.01498 M 4700ml CHIO] - (4+] pH = -log [H+] = -log (0.01498) = 1.82 (d) [H10] = 0.00647 M = CH + ] number of moles of Ch+] = 0.00647MX0.0892 -0.000576 moles number of males y CH +) from Hl.2 0.00362MX0:0732 0.000264 moles Melarity of totalf+] = total moles Molarity of totalff (0.0005767 0.000264) meles total volume (0.0892 +0.0736)

Molarity of CH+] = 0.0008 4 males o. 1624 = 0.00518M pH = -log(ht) = -109 (0.00518) -- 2.28