A very small Steel marble is shown rolling at a constant on a horizontal table

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A very small Steel marble is shown rolling at a constant on a horizontal table

A very small Steel marble is shown rolling at a constant on a horizontal table. The marble leaves the table at M, falls, and hits the ground at P. This is illustrated in the diagram below which is drawn to scale. Calculate the time it took the marble to travel from L to P.

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Answer 1

Answer #1

From point N to point P :

Using the equation of motion :

s = ut + 0.5*at^2

(0.20 i - 0.40 j) = (ux i )*t + 0.5*(-9.8 j)*t^2

So, 20 i - 40 j = (ux*t) i - (4.9*t^2) j

Equating both x and y components :

0.40 = 4.9*t^2 and 0.20 = ux*t

So, t = 0.286 s

So, ux = 0.7 m/s

So, time taken to cover distance from L to N = 0.6/0.7 = 0.857 s

So, total time taken to travel from L to P = 0.857 + 0.286 = 1.14 s <----------- answer

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Answer 2

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A very small Steel marble is shown rolling at a constant on a horizontal table

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