Question

QUESTION 16 The Moon which has mass of about 7.35 1022 kilograms, and it orbits the Earth with an average orbital distance of 384,400 kilometers. Calculate the following for the Moon the magnitude of the average gravitational force exerted by the Earth on the Moon: A. Newtons (use scientific notation and round the coefficient to two decimals) the magnitude of the acceleration due to Earth's gravity at Moon's orbit B. m/s (use scientific notation and round the coefficient to two decimals) the orbital velocity of the Moon C. kms (round your answer to two decimals) - the orbital period of the Moon D. days (round your answer to the nearest integer) the escape velocity from Earth's gravity for a spacecraft launched from the Moon's orbit E. km/s (round your answer to two decimals) Earth's mean radius is RE = 6.37 106 m; Earth's mass is ME = 5.97x1024kg.

Answer 1

solution A FE 6167x10x5697x1024x7-357132 13.844*108)3 = 19.807 x 1019 = 1.98 x 1020 N 1.98x10201 M By a= F = 1.9881020 mmoon 713581022 [2.69x/0- 37 = 2.69 810 3 m/s 12+69810-30/52 C → co vo Vovog a m = 16.67X10 x 5:978124 3.844X108 = 1017.79 m) 5 = 1.02 kms T.02 km/s D- D = 2 gtx 31844810 = 2.3718378106 1017,79 (sec) = 27.45 days 97.45 days. Eg Im ve ²=+GMEM ) Ve= (26) ve = = 2x6-67 X10-11X.5:97X1024 3.8448108 1o44 km)s 1.44 km/s