Question

What is the orbital speed of a satelite in a circular orbit at 8, 129 kilometers above the Earth surface? Express your answer in km/s and round it to two decimals. Earth's mean radius is RE = 6.37 x100 m; Earth's mass is ME = 5.97x104kg. A What is the orbital period of a satelite in a circular orbit at 5,384 kilometers above the Earth surface? Express your answer in minutes (enter "min" for minutes) and round it to the nearest integer. Earth's mean radius is RE = 6.37 x100 mEarth's mass is ME = 5.97x104kg. B. What is the escape velocity from Earth's gravity for a spacecraft launched from the orbit at an altitude of 9,117 kilometers above the Earth surface? Earth's mean radius is RF = 6.37 x 106 m; Earth's mass is MF = 5.97x1024kg. Express your answer in km/s and round it to two decimals What is the escape velocity from Sun's gravity for a spacecraft with mass 4.282 kilograms launched from a distance equal to the Jupiter's average orbital distance from the Sun i.e. 5.2 AU (1AU = 1.5x 100 km)? Msun = 1.99 x 1030 kg. Express your answer in km/s and round it to two decimals. D.

Answer 1

hs 8129 km Earth radius = 6.3 7x10 m = Rp Earth manh 2 5,97 X 1024 kq = ME Height from earth surface h28129x103 het e height of satellite from conter of earth & Roth (6.37x109) + (8129x103) Be 4.499 x10 m Speed of satellite is given by V GM where G 26.673x10 " Nm? JR Gravitational constaand 6673x10-11 x 5.9 4X1024 14.499 x 10 V = 52 41.77 mis [ 5.24 km/gl. speed of satellite

The orbital period is given by T2, 40²R 3 where R (5384 × 103 ) + heigh from carth surfaca (6. 37x108) earth radrus Rz 11.754 x 100 m 4 x 3.442X (11.754% 109) 3 6.673x10 x 5.97x 1024 Tz 126 79.1's 17 72183.4% nonok Timepercodlat satellite T-211.4 min | Time period of satellite or T = R12 min

Question A and B is solved in the attached image