Question

1. What is the molarity of 0.500 L of a potassium chromate solution containing 0.0650 mol of K₂CrO₄?

2. What is the molarity of 4.50 L of a solution containing 0.206 mol of urea [(NH₂)₂CO]?

3. What mass of HCl is present in 825 mL of a 1.25 M solution?

4. What mass of isopropyl alcohol (C₃H₈O) is dissolved in 2.050 L of a 4.45 M aqueous C₃H₈O solution?A 50.0 mL sample of saltwater that is 3.0% m/v is diluted to 950 mL. What is its final mass/volume percent?

Answer 1

* Molarity = 0.065 x 20.130M 0.500 Malarity = 0.206 x = 0.016 M. 4.5 1.25M solution means In 1000 ml Hel present 1.25 mol u 825 Hel 4 1.25 x 825 = 1.031 mot 1070 & Mass of Hela 1.031 x 38.5 8 = 39.78 moles & isopropanot in 2.050 L solution. - 4.45 +2.050 = 9.12 25 moles . Mass of isopropanot - 9-12 25 & 608 2587.358 3% m = mass 50 mL x 100 3x50 - mass - Now - 1.58 % m/v 1.5 x 100 950 -0.158 %