Question

1. Give the IUPAC name for AND classify each of these alcohols as primary, secondary, or tertiary. CH сH, но-сн, — сн-сн, — сн, b. CH3-CH-CH-CH3 a. Он HO d. (CH)2COH с. f. но—сн, — сн, —сH, -сн, —он e. но

Answer 1

. Ho -cho-ch - CH2-CH3 1 2 3 4 :-OM is highest beriority group So humbering from that sia longest carbon Chain is C4 -So butane at Ci carbon -on ol - C2 Carbon - C13 methyl so IUPAC Name willbe 2-methyl butanol-t 1 or 2-methyl butan-1-01 2 at C, carbon -on is present and G is directly joined with + carbon C2 so Poomary alcohol I (13 ) cha –&n - ch cha 4 on longest carbon Cham is Cy- butane at C3 Carbon -C13 methyl at C2 Carbon -on ol so LUPAC Name will be 3-methyl butan-2-01 since -on at ca and C2 directly forned with C, EC3 So Secondary alcohol.

ton longest Carbon chain is co-hexane at C2 Carbon -on -ol at C3 Carbon - CH3 -methyl So IUPAC Name will be 3-methylhexan-2-01 Since C2 is joined with C, 2Cg alcohol So Secondary | 0 ) (C)Con - CH2 &con 3 ch3 at longest carbon chain is Cz - prodane at C2 Carbon -on -ol at C2 Carbon - C13 melhy) So IUPAC Name will be 2-methylpropan-2-ol C2 directly Joshed with 3 carbon so tertiary alcohol

© HO-CH₂ - CH₂ - CH2 -Cha-on 1 2 3 4 longest carbon chain is Cy -butane at ai curbon -on ol at cu carbon -on ol So IUPAC Name will be butan 1,4-diol. Since ( is directly joined with Ca 2 Cy is directly joined with So Both co 2 cn are primary alcohol. - C3 a longest Carbon chain is CG-Cydie * So Cyclo hexane at a carbon -on -ol. at CG Carbon - C2hs -ethyl IUPAC Name will be 3-ethyl cyclohexan-dol So Co is directly joined with C2 266 So Secondary alcohol.