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Use the worked example above to help you solve this problem. The electron and proton of a hydrogen atom are separated by a distance of about 5.62 X 1011 m at some instant. (a) Find the magnitudes of the electric force and the gravitational force that each particle exerts on the other, and the ratio of the electric force, F., to the gravitational force, F F -70E0-8 The response you submitted has the wrong sign. N 3.0E0-47 | F,- resp The response you submitted has the wrong sign. N 2.3E042 F.F Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully (b) Compute the acceleration caused by the electric force of the proton on the electron. Repeat for the gravitational acceleration 7.46E022 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation, Carry out all intermediate results to at least four- digit accuracy to minimize roundoff error: m/s a, = 3.30E-17 m/s HINTS: GETTING STARTED

substitute lgıl = 1821 = e and the distance into Coulombs law to find the electric force. lel2 ( 1.6 x 10-19 C 2-= ( 8.99 x 109 N-m 8.99 x 10 e = Ke c2 (5.3 x 10-11 m 8.2 x 108 N Substitute the masses and distance into Newtons law of gravity to find the gravitational force F, GMemp r2 , m 2 ) (9.11 × 10-31 kg)(1.67 x 10-27 kg N· ( 6.67 x 10.11 5.3 x 10-11 m 3.6 x 1047 N Find the ratio of the two forces. = 2.3 x 1039 (b) Compute the acceleration of the electron caused by the electric force. Repeat for the gravitational acceleration. Use Newtons second law and the electric force found in part (a). 8,2 × 10-8 N me 9.11 x 10 kg = 9.0 × 1022 m/s2 Use Newtons second law and the gravitational force found in part (a) 4.0 × 10.17 m/s2


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