Question

An ophthamologist near your pharmacy asks you to compound 15mL of a 15% naphazoline eye drop solution. You know you'll have to make the solution sotonic so you look up the Evalue for naphazoline which is 0.27. Please calculate how many milligrams of sodium chloride you will add to each vial before sing to 15mL with water Please calculate your answer to one decimal space. Answer: An ophthamologist near your pharmacy asks you to compound 15ml. of a 1.3% amikacin sulfate eye drop solution. You know you'have to make the solution sotonic so you look up the value which is 0.108. Please calculate how many milligrams of sodium chloride you will add to the vial before sing to 15ml with water Please calculate your answer to one decimal space. Answer:

Answer 1

loomL 0.9% Nach solution is Isotonic to our brody fluids, so we have to prepare a solution of 100 mL with o.agNach to get Isotonic solution . ③ In this auestion 15 mL of 1.5% waphazdine eye drops have to Prepare. So to prepare 15mL of Isotonic solution. We need ong, 15 mL of Nad. Toom So amount of Nad is nequired to 998 15 hak - 0.135g S to prepare 15mL of Isotonic saution 100mL- 1.5% Naphazdine solution of 15 mL contain 1.59x 15mL got Naphazoline The amount of Naphazoline present in 1.5% of 15 mL-1.5gx 5 AL = 0.2259 - solution roomt E value for Naphazoline is = 0.27. This means ig of Napha soline equal to 0.279 04 Nad frol Tonicity calculations. so 0.225g of Naphazoline is equivalent to Nadmass = 0.225gx0.27 Equivalent mass of Nad for 6.2259 of Naphazoline = 0.06015 g So This means due to 0.225g of Naphazoline in 15 mb 1.5%. solution to equal to 0.060759. Actually we need 0.1359 Nad. The remaining amount of wad needed = (0.1859-0.0) frol this we have to substract equivalent weight of Nad (0.060 75g) from Actual weight of Nad needed to (0.1859) Prepare Isotonic solution. The Amount Nad needed = 0.1859 – 0.060759= 0.074259 19 = locomg SO = 0.074259 xlooomy. 74.25 mg Amount of Nad needed = 74.25 mg @ 74.3 mg-Anscuen

100 ml . To prepare 15 mL of Isotonic sdution we need page 15 my 0-1959 Nad. As mentioned in the 1st austion * weight of amikacin sulfate present in 1.3% solution of 15mL can be calculated by 18gx 15mm - 0.195 g. 100mb E value fol amikacin sulfate = 0.108 equivalent aright of Nad frol 01959 amikacin suigrate = 0.1959 x 0.108 = 0.021069 Se already 0.021069. A Nad equivalent amount o amikalin is present in solution. The Nad needed = Actual mass of Nad - Nad equivalent mars = 0.1959 - 0.021069 = 0.118949. 19 = 1000mg The mass of Nad needed = 6-113948x 1000mg = 113.94 mg Ang The mass of Nad needed= 113.94 ing @ 118.9 mg