Question

please help

puagag Y saoN (11) SECTION C: FUNDAMENTAL PROBLEMS (Note: Show details of work to get full credit in each problem.) 5. A 20 Kg block slides down a smooth inclined plane. The plane is 10 m long ad is inclined at an angle of 30° with the horizontal.. The coefficient of kinetic friction- 0.3 (a) Draw the free body diagram. (3) 30 (3) (b) Find the Normal force and the Force of friction.

Answer 1

Given is:-

mass of the block  

m = 20kg

A = 30"

Coefficient of kinetic friction  

μα = 0.3

Length of the plane = 10m

Now,

Part - a

The free body diagram of the given problem is as shown below:

Part - b

Normal force frictional force mg sin theta mg cos theta mg

Normal force can be found out by using Newton's second law of motion, thus

N = mgcos

by plugging all the values we get

N = (20kg) (9.8m/s)cos(30°)

which gives us

N = 169.741N

The frictional force is given by

Η = με Ν

thus

f = (0.3) (169.741N)

which gives us

f = 50.9223N