= Objective Knowledge Check Question 6 The rate constant of a certain reaction is known to...

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Answer 1

Answer #1

We can use the following formula

ln(k₂/k₁) = E_a/R x (1/T₁ - 1/T₂)

E_a is the activation energy of the reaction in J/mol = 66000 J/mol
R is the ideal gas constant = 8.3145 J/K·mol
T₁ and T₂ are temperatures in Kelvin

T1 = 273 K And T2 = 273 + 74 = 347 K
k₁ and k₂ are rate constants of reaction at T₁ and T₂

K1 = 2.4 x 10-5 K2 = ?

ln (K2 / 2.4 x 10-5) = 66000 J/mol / 8.3145 J/K·mol [1/273 - 1/347]

ln K2 - ln 2.4 x 10-5 = 6.2

ln K2 = -4.4396

Log K2 = 1.9277

K2 = 1.18 x 10-2 M-1 s-1

Hence rate constant of the reaction at 74⁰C is 1.18 x 10-2 M-1 s-1

Answer 2

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