10)
when -5770.0 KJ of heat is involved, 10 mol of H2O is reacting
So,
for -45 KJ, mol of H2O = -45*10/-5770.0 KJ
= 7.799*10^-2 mol
Molar mass of H2O,
MM = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
use:
mass of H2O,
m = number of mol * molar mass
= 7.799*10^-2 mol * 18.02 g/mol
= 1.405 g
Answer: 1.405 g
Since heat is released, the reaction is exothermic.
Only 1 question at a time please
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