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en a) woled rolo obizno OM 6. Consider the reaction 3A C. If the reaction is second order with a half-life of 20.00 hrs Start
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Answer #1

Given:

Half life = 20 hrs

use relation between rate constant and half life of 2nd order reaction

k = 1/([A]o*half life)

= 1/(0.75*20)

= 6.667*10^-2 M-1.hrs-1

we have:

[A]o = 0.75 M

[A] = 0.25 M

k = 6.667*10^-2 M-1.hrs-1

use integrated rate law for 2nd order reaction

1/[A] = 1/[A]o + k*t

1/(0.25) = 1/(0.75) + 6.667*10^-2*t

4 = 1.333 +6.667*10^-2*t

6.667*10^-2*t = 2.667

t = 40 hrs

Answer: 40 hrs

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