A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of 13.0 mL of KOH. Express your answer numerically.
A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of 12.0 mL of KOH. Express your answer numerically. A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 13.0 mL of HNO3. Express your answer numerically. A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 33.0 mL...
A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of 19.0 mL of KOH. Express your answer numerically.
1) A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of 16.0 mL of KOH.Express your answer numerically. pH=_______ 2) A 75.0-mL volume of 0.200 M NH3 (Kb = 1.8 x10-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 13.0 mL of HNO3.Express your answer numerically. pH=_______ 3) A 52.0-mL volume of 0.35 M CH3COOH (Ka = 1.8 x10-5 ) is titrated with 0.40 M NaOH. Calculate...
A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of 15.0 mL of KOH. Express your answer numerically. pH = SubmitHintsMy AnswersGive UpReview Part Part C A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 27.0 mL of HNO3. Express your answer numerically. pH = SubmitHintsMy AnswersGive UpReview Part Part D A 52.0-mL volume of 0.35 M CH3COOH...
A box with a square base and open top must have a volume of 2048 c m 3 . We wish to find the dimensions of the box that minimize the amount of material used. The length of the base is x and the height is h. Since the base is a square, the surface area of just the base would be: Area = The surface area of just one side would be: Area = The surface area of all...
incase you can’t see the question, it says : How much work is done by the force if the object moves from x= 0.15m to x= 0.60m? (express your answer using two significant figures) Here we leam how to apply the force shown in the figure (Figure 1) moves an object nz0 to z 0.75 m. You may want to review ges 208-212) How much work is done by the force # the object moves from z-0.15 m to z...
You are a member of an alpine rescue team and must get a box of supplies, with mass 2.10 kg , up an incline of constant slope angle 30.0 ∘ so that it reaches a stranded skier who is a vertical distance 2.80 m above the bottom of the incline. There is some friction present; the kinetic coefficient of friction is 6.00×10−2. Since you can't walk up the incline, you give the box a push that gives it an initial...
Name: Date: Problems: 1. The dimensions of a reservoir are as follows: 2-m long, 3-m wide & 4-m high. a) What is the area of the reservoir? b) What is the volume of the reservoir? c) How many gallons of water the reservoir can hold? (Hint: 1 cubic decimeter = 1 liter & 1 gallon = 3.786 liters) 2. A cube has a certain volume. If the dimension of each side is tripled, by what factor will the volume increase?...
Table 3.1 Time, t (s) Position, x (m) tn/t1 Time Squared, t^2 (s^2) (tn)^2/(t1)^2 xn/x1 t1, 0.40 x1, 0.25 1.0 .16 1 1 t2, 0.80 x2, 0.36 2.0 .64 4 1.4 t3, 1.2 x3, 0.52 3.0 1.4 9 2.1 t4, 1.6 x4, 0.71 4.0 2.6 16 2.8 t5, 2.0 x5, 0.95 5.0 4.0 25 3.8 t6, 2.4 x6, 1.2 6.0 5.8 36 4.8 Linear fit equation for Position Vs. Time: 0.545x - 0.0530 Quadratic fit equation for Position Vs. Time:...