Question

Help with questions 1-6 please

Homework #1 Due: Friday January 25, 9:00 A.M. SHOW GENERAL FORMS OF EQUATIONS, HOW YOU DERIVED YOUR ANSWERS AND SHOW UNITS 1. What is the resistance of a thin tube filled with saline solution that is 2 cm in length and has a cross- Name sectional area of 1 x 10s m2? Assume the resistivity of saline solution to be 0.12 m. How much charge is moved over a period of 10 s for a circuit that has a current of 0.2 amperes? A). What is the electrical force set up between two objects separated by 4 m, object 1 has-3 x 10-2 C of charge and object 2 has -4 x 102 C of charge? B) Is the force attractive or repulsive? Assume the two objects in question 3 are of the same physical size and are connected together with a conductor. Will charge move from object 1 to object 2 or from object 2 to object 1? Why? 2. 3. 4. 5. Conceptual question, no calculations are required. You have a 4 V battery, E, and two resistors, R and R2, that you configure in two different ways, A and B, shown below. Assume that R2 is twice as large as R1. A) For configuration A, what is the current ls (expressed in terms of the other currents)? B) for configuration B, what is the current ls (expressed in terms of the other currents)? C) Which configuration (A or B) causes the greatest current output from the battery? D) Without doing any calculations, give the exact value of the change in voltage (in volts) across R1 in configuration A. E) Likewise (i.e. without calculations) give the exact change in voltage across both resistors (i.e. from a point just above R1 to a point just below R2) in configuration B. F) In configuration A, is li greater, equal to, or less than l2? G) In configuration B, is I greater, equal to, or less than l2? The figure below shows three resistors R1-2 Ω, R2 : 4 Ω, and R3-6 Ω configured in four different circuits with a battery, E 2 V. For each circuit, find the current emanating from the battery, I, and the currents passing through each of the three resistors, li, 12, and ls. Show how you got your answers. 6. R, ER

Answer 1

Problem-1

Given is:-

The length of the thin tube L= 2cm or  

Cross sectional area of the tube is  

Resistivity of the saline solution is  

Now,

The resistance of Length L and cross sectional area A and resistivity is given by

by plugging all the values we get

which gives us

Thus the Resistance of the thin tube filled with Saline solution is 200 ohms