1.
At constant temperature and pressure
Volume Number of
moles
mole = (mass/molar mass)
moles of H2 = (10÷2) = 5
moles of He = ( 10÷4) = 2.5
moles of Ne = (10÷20) = 0.2
moles of O2 = (10÷32) = 0.3125
So, Volume containing Hydrogen gas has the largest ballon.
2.
Balanced reaction is
N2 + 3H2 2NH3
1 volume of Nitrogen reacts with 3 volume of Hydrogen.
so, at STP
with 1.5 L of Nitrogen reacts with 3×1.5 = 4.5 L of Hydrogen .
3.
CH3CH2OH + 3 O2 2CO2
+ 3 H2O
1 mol Ethanol reacts with 3 mole oxygen to form 2 mole carbon dioxide.
Hence,
0.9 mol Ethanol reacts with 0.9×3 = 2.7 mol oxygen.
hence, oxygen is limiting reactant.
now mole ratio of oxygen and carbon dioxide
= 3:2
hence, moles of carbon dioxide can be formed
= ×
moles of oxygen
= ×
1.47
= 0.98
now, volume of 1 mole carbon dioxide at STP = 22.4 L
hence, volume of carbon dioxide at STP = 22.4× 0.98 = 21.952 L.
non 7. You are holding four identical balloons each containing 10.0 g of a different gas....