Question

1) Consider the following contingency table that records the results obtained for four samples of fixed...

1) Consider the following contingency table that records the results obtained for four samples of fixed sizes selected from four populations.

Sample Selected From
Population 1 Population 2 Population 3 Population 4
Row 1 34 75 102 71
Row 2 24 58 79 110
Row 3 35 47 72 10

a. calculate the expected frequencies for all cells assuming that the null hypothesis is true.

Round your answers to three decimal places, where required.

Population 1 Population 2 Population 3 Population 4 Total
Row 1
Row 2
Row 3
Total

b. For α=0.025, find the critical value of χ2. Specify the rejection and nonrejection regions on the chi-square distribution curve.

Enter the exact answer from the chi-square distribution table.

χ2=

c. Find the value of the test statistic χ2. Round your answer to three decimal places. The value of the test statistic χ2 is .... ?

2) Bob’s Pest Removal Service specializes in removing wild creatures (skunks, bats, reptiles, etc.) from private homes. He charges $74 to go to a house plus $23per hour for his services. Let y be the total amount (in dollars) paid by a household using Bob’s services and x the number of hours Bob spends capturing and removing the animal(s). The equation for the relationship between x and y is y=23x+74.

a. Bob spent 3 hours removing a coyote from under Alice’s house. How much will he be paid?

3) A researcher took a sample of 1010 years and found the following relationship between x and y, where x is the number of major natural calamities (such as tornadoes, hurricanes, earthquakes, floods, etc.) that occurred during a year and y represents the average annual total profits (in millions of dollars) of a sample of insurance companies in the United States.

^y =337.0−2.0x (For this question, the ^y should show the arrow above the y, I don't know the name of the symbol)

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Answer #1

1. a)

Observed Frequencies
Population 1 Population 2 Population 3 Population 4 Total
Row 1 34 75 102 71 282
Row 2 24 58 79 110 271
Row 3 35 47 72 10 164
Total 93 180 253 191 717
Expected Frequencies
Population 1 Population 2 Population 3 Population 4 Total
Row 1 93 * 282 / 717 = 36.5774 180 * 282 / 717 = 70.795 253 * 282 / 717 = 99.5063 191 * 282 / 717 = 75.1213 282
Row 2 93 * 271 / 717 = 35.1506 180 * 271 / 717 = 68.0335 253 * 271 / 717 = 95.6248 191 * 271 / 717 = 72.1911 271
Row 3 93 * 164 / 717 = 21.272 180 * 164 / 717 = 41.1715 253 * 164 / 717 = 57.8689 191 * 164 / 717 = 43.6876 164
Total 93 180 253 191 717
(fo-fe)²/fe
Row 1 (34 - 36.5774)²/36.5774 = 0.1816 (75 - 70.795)²/70.795 = 0.2498 (102 - 99.5063)²/99.5063 = 0.0625 (71 - 75.1213)²/75.1213 = 0.2261
Row 2 (24 - 35.1506)²/35.1506 = 3.5372 (58 - 68.0335)²/68.0335 = 1.4797 (79 - 95.6248)²/95.6248 = 2.8903 (110 - 72.1911)²/72.1911 = 19.8018
Row 3 (35 - 21.272)²/21.272 = 8.8595 (47 - 41.1715)²/41.1715 = 0.8251 (72 - 57.8689)²/57.8689 = 3.4507 (10 - 43.6876)²/43.6876 = 25.9766

b) df = (r-1)(c-1) = 6

Critical value:

χ²α = CHISQ.INV.RT(0.025, 6) = 14.449

c) Test statistic:

χ² = ∑ ((fo-fe)²/fe) = 67.541

Decision:

As χ² > 14.449, Reject Ho.

-----------

2. ŷ = 74 + (23) x

Predicted value of y at x = 3

ŷ = 74 + (23) * 3 = $ 143

------

3, It is incomplete question.

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