1) Consider the following contingency table that records the results obtained for four samples of fixed sizes selected from four populations.
Sample Selected From | ||||
---|---|---|---|---|
Population 1 | Population 2 | Population 3 | Population 4 | |
Row 1 | 34 | 75 | 102 | 71 |
Row 2 | 24 | 58 | 79 | 110 |
Row 3 | 35 | 47 | 72 | 10 |
a. calculate the expected frequencies for all cells assuming that the null hypothesis is true.
Round your answers to three decimal places, where required.
Population 1 | Population 2 | Population 3 | Population 4 | Total | |
Row 1 | |||||
Row 2 | |||||
Row 3 | |||||
Total |
b. For α=0.025, find the critical value of χ2. Specify the rejection and nonrejection regions on the chi-square distribution curve.
Enter the exact answer from the chi-square distribution table.
χ2=
c. Find the value of the test statistic χ2. Round your answer to three decimal places. The value of the test statistic χ2 is .... ?
2) Bob’s Pest Removal Service specializes in removing wild creatures (skunks, bats, reptiles, etc.) from private homes. He charges $74 to go to a house plus $23per hour for his services. Let y be the total amount (in dollars) paid by a household using Bob’s services and x the number of hours Bob spends capturing and removing the animal(s). The equation for the relationship between x and y is y=23x+74.
a. Bob spent 3 hours removing a coyote from under Alice’s house. How much will he be paid?
3) A researcher took a sample of 1010 years and found the following relationship between x and y, where x is the number of major natural calamities (such as tornadoes, hurricanes, earthquakes, floods, etc.) that occurred during a year and y represents the average annual total profits (in millions of dollars) of a sample of insurance companies in the United States.
^y =337.0−2.0x (For this question, the ^y should show the arrow above the y, I don't know the name of the symbol)
1. a)
Observed Frequencies | |||||
Population 1 | Population 2 | Population 3 | Population 4 | Total | |
Row 1 | 34 | 75 | 102 | 71 | 282 |
Row 2 | 24 | 58 | 79 | 110 | 271 |
Row 3 | 35 | 47 | 72 | 10 | 164 |
Total | 93 | 180 | 253 | 191 | 717 |
Expected Frequencies | |||||
Population 1 | Population 2 | Population 3 | Population 4 | Total | |
Row 1 | 93 * 282 / 717 = 36.5774 | 180 * 282 / 717 = 70.795 | 253 * 282 / 717 = 99.5063 | 191 * 282 / 717 = 75.1213 | 282 |
Row 2 | 93 * 271 / 717 = 35.1506 | 180 * 271 / 717 = 68.0335 | 253 * 271 / 717 = 95.6248 | 191 * 271 / 717 = 72.1911 | 271 |
Row 3 | 93 * 164 / 717 = 21.272 | 180 * 164 / 717 = 41.1715 | 253 * 164 / 717 = 57.8689 | 191 * 164 / 717 = 43.6876 | 164 |
Total | 93 | 180 | 253 | 191 | 717 |
(fo-fe)²/fe | |||||
Row 1 | (34 - 36.5774)²/36.5774 = 0.1816 | (75 - 70.795)²/70.795 = 0.2498 | (102 - 99.5063)²/99.5063 = 0.0625 | (71 - 75.1213)²/75.1213 = 0.2261 | |
Row 2 | (24 - 35.1506)²/35.1506 = 3.5372 | (58 - 68.0335)²/68.0335 = 1.4797 | (79 - 95.6248)²/95.6248 = 2.8903 | (110 - 72.1911)²/72.1911 = 19.8018 | |
Row 3 | (35 - 21.272)²/21.272 = 8.8595 | (47 - 41.1715)²/41.1715 = 0.8251 | (72 - 57.8689)²/57.8689 = 3.4507 | (10 - 43.6876)²/43.6876 = 25.9766 |
b) df = (r-1)(c-1) = 6
Critical value:
χ²α = CHISQ.INV.RT(0.025, 6) = 14.449
c) Test statistic:
χ² = ∑ ((fo-fe)²/fe) = 67.541
Decision:
As χ² > 14.449, Reject Ho.
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2. ŷ = 74 + (23) x
Predicted value of y at x = 3
ŷ = 74 + (23) * 3 = $ 143
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3, It is incomplete question.
1) Consider the following contingency table that records the results obtained for four samples of fixed...
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