Question

For the following reaction, 0.347 moles of iron are mixed with 0.136 moles of chlorine gas. iron(s) + chlorine(g) → iron(III) chloride(s) What is the formula for the limiting reagent? What is the maximum amount of iron(III) chloride that can be produced? moles Reuy Enure Group 9 more group attempts remaining

Answer 1

ironcs) & Chlorine(g) - iron (II) chloride (8) 2 Fe(s) + 3 Clay) 0.347 mol 0.136 mol 2Fecha(s) 0.348. - 2. Bere 0.136 = 2.56 147 > 2 So, Limiting reagent is cl, (o). maximum amount Formula is ch . iron II) chloride that can be of Produced = 0.136 z x2 = 0.0906666667 mol 0.0 qoz mol