Question

Suppose a student diluted and titrated a bleach unknown exactly as described in the experimental procedure except only a sing

for question #5, i divided #3 and #4 and then multiplied by 100. the answer the last expert gave me with the correct sig figs was 5.431 and it was incorrect. ive tried different variations of the answer and i am still getting it wrong. please help
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Answer #1

Solution:

% w/w = (mass of solute / mass of solution) x 100

Thus,

%w/w = mass of NaClO / ( mass of NaClO+ mass of undilluted sample ) x 100

%w/w = 0.05583 g / (0.05583 g + 1.028 g)

= (0.05583 / 1.08383) x 100 = 5.151

= 5.15 %

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