Question

10. On treatment with excess of sodium borohydride in methanol followed by treatment with aqueous acid, which of the followin
7. Starting with the compound with lowest pKa (t.e. most acidic), arrange the following in the order of increasing pKa values
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Answer #1

Question 10. Option D

Explanation: The product formed by the reduction of acetophenone with NaBH4 is 1-phenylethan-1-ol, which is a chiral molecule due to the presence of a chiral center. Hence, a racemic mixture of alcohols is generated.

Question 11. Option B

Explanation: Para-nitrophenol is the most acidic one, hence it has the most Ka value and the least pKa value.

Ortho-chlorophenol is more acidic than para-chlorophenol due to -I effect of Cl-group. Hence the pKa value of ortho-chlorophenol is less than that of para-chlorophenol.

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