Q16.
Reaction 1 : N2 (g) + O2 (g) 2 NO
(g) : Kc1 = 4.3 x 10-25
Reaction 2 : NO2 (g)
NO (g) + 1/2 O2 (g) : Kc2 = 1.25 x
10-5
If we multiply Reaction (2) by a factor of 2, we get
Reaction 3 : 2 NO2 (g)
2 NO (g) + O2 (g)
Kc3 = (Kc2)2
Kc3 = (1.25 x 10-5)2
Kc3 = 1.5625 x 10-10
If we reverse Reaction (3), we get
Reaction 4 : 2 NO (g) + O2 (g) 2
NO2 (g)
Kc4 = 1/Kc3
Kc4 = 1/(1.5625 x 10-10)
Kc4 = 6.4 x 109
Now add Reaction (1) and Reaction (4), we get
N2 (g) + 2 O2 (g) 2
NO2 (g)
This is the desired reaction.
Kc = (Kc1) * (Kc4)
Kc = (4.3 x 10-25) * (6.4 x 109)
Kc = 2.752 x 10-15
Understanding reactions involving normal components of air is essential for solving problems 16. dealing with atmos...
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Determine the equilibrium constant for the following reaction.
Please show work, thank you!
(forgot to add the equations)
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