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An object located 30.0 cm in front of a lens forms an image on a screen 7.80 cm behind the lens. (a) Find the focal length of

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=> object distance (U) = 30cm a) image distance (u) = 7.8ocna We have - It I 30 7.8 - 0.033 +0.128 =) f da bi 3) 6.211 cm 5)

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