Question

if an engine works at 50% of its maximum efficiency and the engine operates between temperatures 500K and 200K. Determine the work performing in each cycle if absorbs 1200J of heat.

Answer 1

First calculate the maximum efficiency from the given conditions.

Given that –

T1 = 200 K

T2 = 500 K

So, maximum efficiency of the engine -, η = (T2 – T1) / T2

                                                                = (500 K – 200 K) / 500K = 0.60 = 60 %

Now the engine works at 50% of its maximum efficiency.

Input power for the engine, Pi = 1200 J

Therefore, work performed by the engine in each cycle, Pw = Pi x η x (50/100)

                                                                                           = 1200 J x (60/100) x (50/100) = 360 J (Answer)