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Answer #1


Hot temperature T = 800 K
Cold temeprature T ' = 300 K
Maximum efficiency of the heat engine e = 1-( T ' / T )
= 1 - (3/8)
= 0.625
80% of maximum possible efficiency is 0.625*(80/100) = 0.5...

in percentage the answer is 0.5*100 = 50%

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Answer #2

Nth=1-300/800

=0.625

80 % of 0.625

=0.5

=50 % ans

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A heat engine operates between 800 K and 300 K, but its efficiency is only 80%...
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