here from given information:
n(D) =25 (as 25 house have dogs) ; n(C n D)= 7 (as 7 have both cats and dogs)
n(C' n D') =18
as n(C u D) =50-n(C' n D')=50-18=32
a)
n(D n Cc )=n(D) -n(D n C)=25-7=18
b)
n(C) =n(C u D)+n(C n D)-P(D)=32+7-25=14
c)
n(C n D') =n(C)-n(C n D)=14-7=7
d) n(C u D)-n(C n D)=32-7=25
2. In an isolated housing area consisting of 50 households, the residents are allowed to have...
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