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need help with lab calculations
not sure which equation to use?
average molarity of NaOH is .0996M
Trial 2 Concentration of Unknown HCI Unknown # Trial 1 volume of HCI (in mL) volume of NaOH (in mL) Mof HCI? average M of HCI
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Answer #1

veagemelasiy dNaoH (N, 0416H ThialD Volume H Volume Na oH (V) un NVNV (Мьон) (на) Naa & HC oi. N& NCencmhakns Volu mes NaH &

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