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[18] Calculate the molarity of a solution made by dissolving 23.4 g of sodium sulfate (NagSO4) in enough water to form 125 mL
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Answer #1

142.04 gm of sodium sulfate dissolved in 1000 ml is 1 Molar solution

Then, 23.4 gm of 125 ml of water have what molarity

molecular weight of sodium sulfate = 142

thus, moles of sodium sulfate = (23.4/142) = 0.165 mol

volume of solution = 125 mL = 0.125 L

Thus molarity of solution = (0.165/0.125) = 1.32 M

Thus molarity of solution = 1.32 M

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