Question

Solutions practice problems. calculate how much of each ingredient you would need to make the solution CIRCLE YOUR FINAL ANSWERS. Be sure to include the correct units with your answer. Molecular weights: SDS-288.38 g/mol Tris (base) = 121.1 g/mol EDTA = 372.2 g/mol Sodium acetate 82.03 g/mol Tris maleate = 237.2 g/mol Magnesium sulfate heptahyrdate=246.5 g/mol Sodium hydroxide - 40.00 g/mol (can calculate the MW for simple compounds) 1) 200 mL of 25% SOS 2) 60 ml alkaline lysis buffer (0.2 M sodium hydroxide; 1% SDS) 43) 250 mL of leech saline (115 ml NaCl; 1.8 mm CaCl2; 4 mM KCI; 10 mM Tris maleate (pH 7.4)) 4) 10 ml of 0.2 M NaCI

Answer 1

The amount of each substance is calculated:

1) mSDS = 200 mL * (25 g / 100 mL) = 50 g SDS

2) m NaOH = 0.2 M * 0.06 L * 40 g / mol = 0.48 g

m SDS = 60 mL * (1 g / 100 mL) = 0.6 g

3) m NaCl = 0.25 L * 0.115 M * 58.44 g / mol = 1.68 g

4) m NaCl = 0.2 M * 0.01 L * 58.44 g / mol = 0.117 g

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