Calculate how much of each solution (and water!) you would need to make 100 mLs of a 0.1 M Tris/0.05M EDTA solution from 1M Tris and 1 M EDTA stock solutions?
Using the law of conservation of mass,
M1. V1 = M2 .V2
(1 denotes the values from the dilution we require and 2 denotes the values of stock solution)
0.1 * 100 = 1 * x
therefore x = 0.1 * 100/ 1
= 10 mL
therefore take 10mL from tris stock and mix it with 90mL water
0.05 * 100 = 1 * x
x = 0.05 * 100/1
x= 5mL
thereforetake 5mL from EDTA stock and mix with 95mL water to get 100mL of 0.05M EDTA
Calculate how much of each solution (and water!) you would need to make 100 mLs of...
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