Question

2) Starting with .200 M Fe3+ solution, how can yo Fe solution, how can you prepare 25.0 mL solution that is 0.0800 M? 3) Befo
0 0
Add a comment Improve this question Transcribed image text
Answer #1

2) Using the relation M * V = constant, with initial volume V we get:

0.2 * V = 0.08 * 25

Solving, we get: V = 10 mL

Therefore, we take 10 mL of the 0.2 M solution and add 15 mL of distilled water to it to make it 25 mL of 0.08 M

3) Absorbance measurements must allow the light to be absorbed only by the solution in the cuvette. Dirt and fingerprints wil scatter the light giving an error in the absorbance value

Add a comment
Know the answer?
Add Answer to:
2) Starting with .200 M Fe3+ solution, how can yo Fe solution, how can you prepare...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Starting with a 25.0 mL 5.0 M CuSO4 solution, show how you would prepare 25.0 mL...

    Starting with a 25.0 mL 5.0 M CuSO4 solution, show how you would prepare 25.0 mL of each of the following solutions: 2.5 M, 1.0 M, 0.5 M CuSO4. Assuming you have only one 25.0 mL flask to prepare three solutions, should you prepare the most concentrated or dilute solution first? Explain. Does the volumetric flask have to be dry before you use it to prepare the next solution? Explain. When using a pipet that has the marking TD on...

  • Describe how you would prepare 200 mL of a 0.25 M solution of NaOH.

    Describe how you would prepare 200 mL of a 0.25 M solution of NaOH.

  • You need to prepare 200 mL of a 0.4 M solution of ammonium hydroxide (NH4OH) You...

    You need to prepare 200 mL of a 0.4 M solution of ammonium hydroxide (NH4OH) You have 80 mL of a 0.5 M NHOH solution and 40 mL of a 7.5% (w/v) NH4OH solution. What volume of 7.5% NHOH and water needs to be added to the 80 mL of 0.5 M NH4OH solution to make up 200 mL of 0.4 M NH4OH? Molar mass of NH4OH 35.04 g/mol % (weight / volume) means mass (in g) in volume (100...

  • ELECTROCHEMISTRY PRE-LAB ASSIGNMENT: Use the data given below to do similar calculations as you w...

    Pre Lab : Electrochemistry ELECTROCHEMISTRY PRE-LAB ASSIGNMENT: Use the data given below to do similar calculations as you will be performing in today's lab Part A: Verification of the Nernst equation The electrochemical cell to be used can be represented using conventional cell notation as: Ag(s) l Agcl(s) HCII M)|Ce(aq),Ce (a) Pts) [Ce4+]-0. | 0 M [Ce3+]-0. I 0 M Room temperature 21.6°C voltage(m V Solution mL of Ce+ solution mL of Ces solution 25.0 25.0 25.0 25.0 25.0 24.0...

  • A student made solution #3 using the experimental method in this lab, and measured an absorbance of 0.559. The starting...

    A student made solution #3 using the experimental method in this lab, and measured an absorbance of 0.559. The starting reagents are 2.00 x 10-3 M Fe(NO3)3 and 2.00 x 10-3 M KSCN. The amount of absorption is proportional to the concentration of FeSCN2+. This relationship – true for many solutions – is called “Beer’s Law”, and has the simple equation: A = bc where “A” is the absorption, “b” is 5174.6 for FeSCN2+ and “c” is molarity Make Five...

  • How can the colouration (or lack thereof) of the solutions be explained? How would you expect...

    How can the colouration (or lack thereof) of the solutions be explained? How would you expect DELTAO to change as the number of L ligands about the metal increases or decreases, and why? UJUS ML PULUUPIUIUMLILI There are several types of spectrophotometers. Be sure to ask the instructor if you are unsure how to use the one you are assigned. You will be measuring absorbances at different wavelengths so it is essential to know how to quickly adjust the settings...

  • The actual concentration of the stock [Fe(NO3)3] solution you will use in lab will be posted...

    The actual concentration of the stock [Fe(NO3)3] solution you will use in lab will be posted on D2L. Be sure to record the concentration value matching YOUR lab room and use it in your laboratory worksheet! Consider test tube #5 that you will prepare in Part 1 of the laboratory (Table A). If your  dilute solution of Fe(NO3)3 had a concentration of 0.00087 M, predict the initial concentration of the Fe3+ ions, [Fe3+]0 in test tube #5, once you have added...

  • Determine the equilibrium concentration of FeSCN2+ in each solution. (Page below are the initial concentrations of...

    Determine the equilibrium concentration of FeSCN2+ in each solution. (Page below are the initial concentrations of FE3+ and scn- for each solution ) Secondly, use stoichiometry to determine equilibrium FE3+ and SCN -. ( concentration used for FE and KSCN are both 0.002M ) the absorbance of each standard in the same test tube used to blank the spectrophoto standards from least to most concentrated, rinsing with a small amount of the next sta tilling the test tube. Record absorbance...

  • 1. How would you prepare 125 ml of a 10% (v/v) solution of acetic acid in...

    1. How would you prepare 125 ml of a 10% (v/v) solution of acetic acid in H2O? 2. How would you prepare 60 ml of a 5% (W/V) NaCl solution in H20? 3. How would you prepare 3 ml of 82% solution A and 18% solution B? 4. 5 ml of a 2.0 mg/ml protein solution contains mg protein. a. If 1.0 ug/ml of pigment X shows an absorbance of 0.059 at 370nm, then what is the concentration of a...

  • Describe how you can prepare the following solution. A 492.6 g solution of a 1.98 %...

    Describe how you can prepare the following solution. A 492.6 g solution of a 1.98 % (w/w) benzene solution in chloroform. Calculate the morality of an aqueous solution made with 768.93 mg of (NH_4)_2SO_4 to a final volume of 675 mL?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT