Given:
Half life = 5730 years
use relation between rate constant and half life of 1st order reaction
k = (ln 2) / k
= 0.693/(half life)
= 0.693/(5730)
= 1.209*10^-4 years-1
we have:
[C]o = 24
[C] = 3
k = 1.209*10^-4 years-1
use integrated rate law for 1st order reaction
ln[C] = ln[C]o - k*t
ln(3) = ln(24) - 1.209*10^-4*t
1.099 = 3.178 - 1.209*10^-4*t
1.209*10^-4*t = 2.079
t = 1.719*10^4 years
Answer: 1.72*10^4 years
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