Number of moles of NaOH = molarity * volume of solution in L
Number of moles of NaOH = 0.46 * 0.0255 = 0.0117 mole
From the balanced equation we can say that
1 mole of NaOH requires 1 mole of HCl so
0.0117 mole of NaOH will require
= 0.0117 mole of NaOH *(1 mole of HCl / 1 mole of NaOH)
= 0.0117 mole of HCl
molarity of HCl = number of moles of HCl / volume of solution in L
molarity of HCl = 0.0117 / 0.018 = 0.650 M
Therefore, the molarity of HCl = 0.650 M
What is the molarity of an HCl solution il 25.5 mL of a 0.46 M NaOll...
What is the molarity of an HCl solution iſ 28.5 mL of 0.16 M NaOH are needed to neutralize 15.0 mL of the sample? MHCI
If 34.50 mL of 0.2486 M NaOH is needed to neutralize 10.0mL of HCl solution, what is the molarity of the HCl?
A solution of 0.154 M NaOH is used to neutralize 25.5 mL of a H2SO4 solution. If 25.0 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution? H2SO4(aq)+2NaOH(aq)→2H2O(l)+Na2SO4(aq)
A. How many milliliters of 0.110 M HCl are needed to completely neutralize 55.0 mL of 0.107 M Ba(OH)2 solution? Express the volume in milliliters to three significant digits. B. How many milliliters of 0.125 M H2SO4 are needed to neutralize 0.170 g of NaOH? Express the volume in milliliters to three significant digits. C. If 55.0 mL of BaCl2 solution is needed to precipitate all the sulfate ion in a 746 mg sample of Na2SO4, what is the molarity of the solution? Express the molarity...
Calculate the concentration (in molarity) of an NaOH solution if 25.0 mL of the solution is needed to neutralize 15.5 mL of a 0.305 M HCl solution.
(a) How many milliliters of 0.155 M HCl are needed to neutralize completely 35.0 mL of 0.101 M Ba(OH)2 solution? ml (b) How many milliliters of 2.50 M H2SO4 are needed to neutralize 50.0 g of NaOH? mL (c) If 54.8 mL of BaCl2 solution is needed to precipitate all the sulfate in a 544 mg sample of Na2SO4 (forming BaSO4), what is the molarity of the solution? M (d) If 47.5 mL of 0.375 M HCl solution is needed...
(a) How many milliliters of 0.155 M HCl are needed to neutralize completely 35.0 mL of 0.101 M Ba(OH)2 solution? (b) How many milliliters of 2.50 M H2SO4 are needed to neutralize 75.0 g of NaOH? (c) If 56.8 mL of BaCl2 solution is needed to precipitate all the sulfate in a 554 mg sample of Na2SO4 (forming BaSO4), what is the molarity of the solution? (d) If 47.5 mL of 0.250 M HCl solution is needed to neutralize a...
(0) How many milliers of 0.155 M HCl are needed to neutralize completely 45.0 ml of 0.101 M Ba(OH)2 solution? ml (b) How many milliliters of 2.50 M H2SO4 are needed to neutralize 25.0 9 of NaOH? (c) If 54.8 ml of BaCl solution is needed to precipitate all the sulfate in a 544 mg sample of Na2SO4 (forming Basod), what is the molarity of the solution? (d) If 37.5 mL of 0.250 M HCl solution is needed to neutralize...
What is the molarity of a solution of HCl if 6.00 mL of the HCl solution is titrated with 26.8 mL of a 0.125 M NaOH solution? HCl(aq)+NaOH(aq)→H2O(l)+NaCl(aq)
d. (5 Points) A 150 mL portion of 0.250 M HCl solution was titrated with NaOH; It took 100. mL of a 0.375 M base to neutralize the sample. If only 70.0 mL of NaOH were added to the 150.0 mL portion of HCl, what is the molarity of the HCl remaining in solution?