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late the mass of P4010 produced along 15000. calories of 4. Calculate th heat. stem absorbs 105 kJ of heat from its surroundi
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Answer #1

4. The standard heat of formation of P4O10(s) = -2984 kj = -2984000 kj/mole

The standard heat of formation of P4O10(s) = -713.193116 kcal = -713193.116 calories

i. e 713193.116 calories of heat is produced during formation of 283.886 gms of P4O10

15000 calories of heat is produced during formation of (15000*283.886)/713193.116 = 5.97 gms of P4O10

The mass of P4O10 used is 5.97 gms

5. When a system does work (w) on the surroundings, its internal energy decreases. In this case, work is taken as negative (-w). Now, if 'q' is the amount of heat absorbed by the system and 'w' is the work done by the system, then change in internal energy becomes

\DeltaE = q -w = 105000-96 = 104904 j = 104.904 kj

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