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PRE-LAB ASSIGNMENT 1) Write the balanced net ionic equation for the reaction between MnO4-ion and Feation in acid solution. 2
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Answer #1

1) The net ionic reaction between MnO4- and Fe2+ is as follows:

5 Fe2+ + MnO4- + 8 H+ = 5 Fe3+ + Mn2+ + 4 H2O

2) In the above reaction the ratio between MnO4- and Fe2+ is 1 : 5

1 : 5 = 1.2*10-2 : x

x = 16.1 moles Fe2+ that can be oxidized by 1.2*10-2 moles of MnO4-.

3) a. Molarity of MnO4- is 0.024M. From this we can find the number of moles is 0.874 moles

b. Given amount of Fe2+ is 1.750 g and the molar mass of Fe2+ is 55.845 g.

The number moles required is given by ratio of given amount/molar mass .

So, the moles of Fe2+ is 0.0313 moles.

c. The sample contains 1.75 g of iron.

d. The percentage of iron present in sample is 0.175%

4) Percentage of iron present in Fe(NH4)2(SO4)2.6H2O is 14.32%

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