Question

Use a significance level of a = 0.05 to test the claim that u 19.6. The sample data consists of 10 scores for which = 20.1 and s=4.1. State the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. Using a 0.10, state your conclusions about the claim. Use Minitab to compute the P-value. Hou = 20.1 Hau 20.1 Test statistic: t = 0.39. P-Value: P = 0.70872. Accept Ho: a = 20.1. Since P>, there is not sufficient evidence to support the claim that the mean is different from 20.1. Hou = 19.6 Hau 19.6 Test statistic: t = 0.39. P-Value: P=0.3545. Reject Hon = 19.6. Since P>, there is sufficient evidence to support the claim that the mean is different from 19.6. Hou = 19.6 Ha: u 19.6 Test statistic: t = 0.39. P-Value: P=0.709. Reject Hou = 19.6. Since P>, there is sufficient evidence to support the claim that the mean is different from 19.6. O Ho: 1 = 19.6 Ha: # 19.6 Test statistic: t = 0.39. P-Value: P =0.709. Retain Ho u = 19.6. Since P>, there is not sufficient evidence to support the claim that the mean is different from 19.6. O Hou = 19.6 Hau 19.6 Test statistic: t = 0.39. P-Value: P =0.709. Retain Ho u = 19.6. Since P> , there is sufficient evidence to support the claim that the mean is different from 19.6.

Answer 1

riven 7=2011 Saul nalo Ho: M=19.6 Hii U$19.6 ūrill 2011-19.6 - 0.3856 ♡ 0.38 ti sia Worsie 15:0-39 If we consider t=0.3856 will get P=0.109 it is two tailed test 2PCE >4-1) : PP16 > 0.39) I : 07056 [P: 0.109 > 2 (0.1)) Do not reject Ho. "Retain Hol=19.6 since pod, evidence to support the claim ophon u is correct. there is not sufficient that u & 19.6.